← VCE Pseudocode

Arithmetic Operators in Pseudocode

The pseudocode operator that returns the remainder after integer division. Example: 10 MOD 3 gives 1 because 10 divided by 3 is 3 remainder 1

Part of: VCE Pseudo Code — Module 7, VCE Software Development - U3O1 - Programming — Module 62, 7-8 Digital Technologies: Designing and tracing algorithms — Module 7, QCE Digital Solutions Unit 1 — Algorithms and Programming Techniques — Module 16, QCE Digital Solutions Unit 2 — Data-Driven Problems and Solution Requirements — Module 96, QCE Digital Solutions Unit 2 — Data and Programming Techniques — Module 130, QCE Digital Solutions Unit 3 — Real-World Problems and Solution Requirements — Module 61, QCE Digital Solutions Unit 4 — Prototype Digital Data Exchanges — Module 43, WA Computer Science ATAR Year 11 — Pseudocode and Algorithm Design — Module 19, WA Computer Science ATAR Year 11 — Control Structures and Data Types — Module 22

Understanding Arithmetic Operators in Pseudocode in VCE Pseudocode

What it does: 17 DIV 5 = 3 because 5 goes into 17 three times with remainder 2. DIV discards the remainder and returns only the whole number 3. Both + and - are standard arithmetic operators in pseudocode. They work in assignment expressions exactly as in mathematics. The asterisk * is the correct multiplication operator in pseudocode. The letter x is not a valid operator and would be interpreted as a variable name. The caret ^ is not a standard VCAA pseudocode operator. To find 20%, divide by 5 using the / operator: tax <- income / 5.

Common mistakes: length x width uses the letter x as a multiplication symbol, which is not valid in pseudocode. The correct operator for multiplication is the asterisk *. The line should read area <- length * width. Line 2 is wrong. The backslash \ is not a valid pseudocode operator. For division the correct operator is the forward slash /. The line should read average <- total / 3. Line 3 is wrong.

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Learning

Duo

Which operator is used for multiplication in VCAA pseudocode?

* — for example: area <- length * widthx — for example: area <- length x width

Matches

area <- length x width

↓

Wrong — x is not a valid pseudocode operator. The multiplication operator is the asterisk *. The correct form is `area <- length * width`

Applying

Meanings

Term

MOD

Meaning

The pseudocode operator that returns the remainder after integer division. Example: 10 MOD 3 gives 1 because 10 divided by 3 is 3 remainder 1

Practice

Algorithm: compute bill

Testing

Gaps

total <- price quantity

Check Answer

Spots

2input length, width

3area <- length x width

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Quick Questions

1. Which operator is used for multiplication in VCAA pseudocode?

A. * — for example: area <- length * width ✓

B. x — for example: area <- length x width

The asterisk * is the correct multiplication operator in pseudocode. The letter x is not a valid operator and would be interpreted as a variable name.

2. What does the MOD operator return in pseudocode?

A. The whole number result of division

B. The remainder after integer division ✓

MOD returns the remainder. For example: 10 MOD 3 gives 1 because 10 / 3 is 3 with remainder 1. DIV returns the whole number result.

3. What does total DIV 4 return when total is 10?

A. 2.5 — the exact decimal result

B. 2 — the whole number part of 10 / 4 ✓

DIV performs integer division and discards any remainder. 10 DIV 4 = 2 because 4 goes into 10 twice with a remainder of 2. The remainder is discarded.

4. Which correctly subtracts cost from revenue in pseudocode?

A. profit <- revenue - cost ✓

B. profit <- revenue -- cost

A single minus sign - is the subtraction operator in pseudocode. A double minus -- is not valid pseudocode syntax.

5. What does 15 MOD 4 evaluate to in pseudocode?

A. 3 — the remainder when 15 is divided by 4 ✓

B. 3.75 — the decimal result of 15 divided by 4

MOD returns only the remainder as an integer. 15 / 4 = 3 remainder 3, so 15 MOD 4 = 3. Decimal results belong to the / operator.

Match the Pairs

area <- length * width → Multiplies length by width using the * operator and stores the result in area

remainder <- total MOD 7 → Divides total by 7 and stores only the remainder in the variable remainder — for example if total is 22 the result is 1

DIV returns the whole number part of a division, discarding any remainder → quotient <- 17 DIV 5

The + operator adds two values and the - operator subtracts one value from another → total <- a + b profit <- revenue - cost

area <- length x width → Wrong — x is not a valid pseudocode operator. The multiplication operator is the asterisk *. The correct form is `area <- length * width`

result <- a ^ 2 → Wrong — the caret ^ is not a standard VCAA pseudocode operator. To square a value, multiply it by itself: `result <- a * a`

Key Term

MOD

The pseudocode operator that returns the remainder after integer division. Example: 10 MOD 3 gives 1 because 10 divided by 3 is 3 remainder 1

Fill in the Blanks

1. total <- price * quantity

Hint: Type the arithmetic operator used to multiply two values together

2. average <- (a + b) / 2

Hint: Type the arithmetic operator used to divide the sum by 2

3. remainder <- total MOD 7

Hint: Type the pseudocode operator that returns the remainder after dividing total by 7

4. quotient <- total DIV 4

Hint: Type the pseudocode operator that returns the whole number result of dividing total by 4

5. profit <- revenue - cost

Hint: Type the arithmetic operator used to subtract cost from revenue

Spot the Error

Question 1

A Algorithm: compute area

B input length, width

C area <- length x width

D print area

Line C — `length x width` uses the letter x as a multiplication symbol, which is not valid in pseudocode. The correct operator for multiplication is the asterisk *. The line should read `area <- length * width`. Line 2 is wrong.

Question 2

A Algorithm: find average

B input a, b, c

C total <- a + b + c

D average <- total \ 3

E print average

Line D — The backslash \ is not a valid pseudocode operator. For division the correct operator is the forward slash /. The line should read `average <- total / 3`. Line 3 is wrong.

Question 3

A Algorithm: get remainder

B input n

C remainder <- n MOD 5

D print remainder

Line A — The algorithm header is missing its colon. The correct form is `Algorithm: get remainder` with a colon after the keyword Algorithm. Line 0 is wrong.

Question 4

A Algorithm: integer divide

B input total

C result <- total DIV 4

D print results

Line D — `print results` references a variable called `results` but the variable assigned on line 2 is called `result`. Variable names must match exactly. The line should read `print result`. Line 3 is wrong.

Question 5

A Algorithm: calculate tax

B input income

C tax <- income * 0.2

D net <- income - tax

E print net

Line C — `income * 0.2` uses a decimal multiplier not typical in VCAA pseudocode which conventionally uses integer or variable operands. The more standard form expresses 20% as `tax <- income / 5`. Line 2 is wrong.

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