A menu loop to control user interactions

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Quick Questions

Shade in the A or B circle for each question.

1. Which loop keeps a menu showing until the user chooses to quit?

A while True: ... break when the choice is 'Q'

B for i in range(1): ... then the program ends

2. Which order is correct inside a menu loop?

A Show the menu, read the choice, call the matching function

B Call the matching function, read the choice, show the menu

3. Which code dispatches the choice to the right function?

A if choice = '1': add_item() elif choice = '2': view_items()

B if choice == '1': add_item() elif choice == '2': view_items()

4. Why use elif rather than a separate if for each menu option?

A elif makes the menu loop run faster than if

B Only one matching branch runs, and the else can catch anything left over

5. The user types 'x', which is not a menu option. What should the menu loop do?

A Show an error message in an else branch and display the menu again

B End the program without a message

Match the Pairs

Draw a line connecting each item on the left to its match on the right.

Left column		Right column
1while True:		AThe quit branch never uses break, so the loop never ends and the menu keeps appearing after the user chooses quit.
2elif choice == "2":		BStarts a menu loop that keeps showing the menu until the program reaches a break
3An invalid choice is handled by an else branch that shows an error and lets the loop repeat		Celse: print("Invalid choice")
4The quit option ends the menu loop and returns control to the rest of the program		DChecks whether the user picked option 2 and, if so, runs that option's function
5while True: choice = input("Choice: ") if choice == "3": print("Bye")		EA single = assigns a value instead of comparing. The condition needs == to check the user's choice.
6while True: choice = input("Choice: ") if choice = "1": add_item()		Felif choice == "3": break

Definitions

while True:

Fill in the Blanks

Complete each line of code by filling in the missing parts.

_____ True: choice = input("Choice: ") if choice == "1":

if choice == "1": addItem() ____ choice == "2":

elif choice == "q": break ____:

elif choice == "3": _____ else:

while True: showMenu() choice = _____("Choice: ")

Spot the Error

Shade in the letter of the line that contains an error.

Question 1

A while True:

B choice = input("Choice: ")

C if choice = "1":

D start_game()

E elif choice == "2":

F break

Question 2

A while True:

B print("1 Play 2 Quit")

C choice = input("Choice: "

D if choice == "2":

E break

F play()

Question 3

A while False:

B choice = input("Choice: ")

C if choice == "Q":

D break

E print("Invalid choice")

Question 4

A while True:

B choice == input("> ")

C if choice == "Q":

D break

E else:

F print("Invalid choice")

Question 5

A while True:

B choice = input("> ")

C if choice == 1:

D view_scores()

E elif choice == "Q":

F break

Answer Key

A menu loop to control user interactions

Section A: Quick Questions

A — while True: ... break when the choice is 'Q'

A — Show the menu, read the choice, call the matching function

B — if choice == '1': add_item() elif choice == '2': view_items()

B — Only one matching branch runs, and the else can catch anything left over

A — Show an error message in an else branch and display the menu again

Section B: Match the Pairs

while True: → Starts a menu loop that keeps showing the menu until the program reaches a break

elif choice == "2": → Checks whether the user picked option 2 and, if so, runs that option's function

An invalid choice is handled by an else branch that shows an error and lets the loop repeat → else: print("Invalid choice")

The quit option ends the menu loop and returns control to the rest of the program → elif choice == "3": break

while True: choice = input("Choice: ") if choice == "3": print("Bye") → The quit branch never uses break, so the loop never ends and the menu keeps appearing after the user chooses quit.

while True: choice = input("Choice: ") if choice = "1": add_item() → A single = assigns a value instead of comparing. The condition needs == to check the user's choice.

Section C: Definitions

while True: — Starts a menu loop that repeats forever: show options, read a choice, call the matching function with if/elif, reject invalid input, and break when the user picks quit.

Section D: Fill in the Blanks

while True:
    choice = input("Choice: ")
    if choice == "1":

    if choice == "1":
        addItem()
    elif choice == "2":

    elif choice == "q":
        break
    else:

    elif choice == "3":
        break
    else:

while True:
    showMenu()
    choice = input("Choice: ")

Section E: Spot the Error

C — A single = assigns a value and is not allowed in an if condition. Use == to compare the user's choice with "1".

C — The input() call is missing its closing bracket, which causes a SyntaxError. It should end with ) like this: input("Choice: ").

A — A menu loop must start with while True: so it keeps running until the user chooses to quit. while False: never runs the menu at all.

B — == compares values and does not store anything, so choice is never created. Use a single = to assign the user's input to choice.

C — input() always returns a string, so choice is "1" and never equals the number 1. The menu option would never be matched. Compare with the string "1".