Arithmetic operators in Cambridge pseudocode
Name:
Date:
Class:
A
Quick Questions
Shade in the A or B circle for each question.
1. What is the value of 17 DIV 5?
2. What is the value of 17 MOD 5?
3. Which result does 7 / 2 give in Cambridge pseudocode?
4. Which expression gives the whole-number quotient of 20 divided by 6?
5. What is the value of 2 + 3 * 4?
B
Match the Pairs
Draw a line connecting each item on the left to its match on the right.
| Left column | Right column | |
|---|---|---|
| 117 DIV 5 | ADIV gives the quotient, not the remainder. To test for even, use Number MOD 2 = 0. | |
| 217 MOD 5 | BResult ← 7 / 2 | |
| 3The / operator gives a real result, so dividing 7 by 2 gives 3.5 | C/ gives the real result 3.4, not the whole number 3. Use 17 DIV 5 to get the whole-number quotient. | |
| 4Brackets set the order, so the addition is done before the multiplication and the answer is 20 | DTotal ← (2 + 3) * 4 | |
| 5Pages ← 17 / 5 OUTPUT Pages (meant to find whole pages, expecting 3) | EGives the remainder after dividing, so the result is 2 | |
| 6IF Number DIV 2 = 0 THEN (meant to test for an even number) | FGives the whole-number quotient, so the result is 3 |
C
Definitions
+ - * / DIV MOD
D
Fill in the Blanks
Complete each line of code by filling in the missing parts.
1.
Quotient ← 17 ___ 5
2.
Remainder ← 17 ___ 5
3.
Average ← Total _ Count
4.
Hours ← TotalMins ___ 60
Mins ← TotalMins MOD 60
5.
Mean ← _Score1 + Score2) / 2
E
Spot the Error
Shade in the letter of the line that contains an error.
Question 1
A
DECLARE Rem : INTEGER
B
Num ← 17
C
Rem ← Num DIV 5
D
OUTPUT Rem
Question 2
A
Minutes ← 135
B
Hours ← Minutes MOD 60
C
Left ← Minutes MOD 60
D
OUTPUT Hours, Left
Question 3
A
INPUT Num
B
IF Num DIV 2 = 0 THEN
C
OUTPUT "Even"
D
ENDIF
Question 4
A
A ← 80
B
B ← 70
C
C ← 90
D
Avg ← A + B + C / 3
E
OUTPUT Avg
Question 5
A
Price ← 4.50
B
Total ← Price x 3
C
OUTPUT Total
Answer Key
Arithmetic operators in Cambridge pseudocode
Section A: Quick Questions
Q1
B — 3
Q2
B — 2
Q3
A — 3.5
Q4
A — 20 DIV 6
Q5
A — 14
Section B: Match the Pairs
Q1
17 DIV 5 → Gives the whole-number quotient, so the result is 3
Q2
17 MOD 5 → Gives the remainder after dividing, so the result is 2
Q3
The / operator gives a real result, so dividing 7 by 2 gives 3.5 → Result ← 7 / 2
Q4
Brackets set the order, so the addition is done before the multiplication and the answer is 20 → Total ← (2 + 3) * 4
Q5
Pages ← 17 / 5 OUTPUT Pages (meant to find whole pages, expecting 3) → / gives the real result 3.4, not the whole number 3. Use 17 DIV 5 to get the whole-number quotient.
Q6
IF Number DIV 2 = 0 THEN (meant to test for an even number) → DIV gives the quotient, not the remainder. To test for even, use Number MOD 2 = 0.
Section C: Definitions
Q1
+ - * / DIV MOD — Arithmetic operators: + - * / calculate with numbers, and / gives a real result. DIV gives the whole-number quotient and MOD the remainder, so 17 DIV 5 is 3 and 17 MOD 5 is 2.Section D: Fill in the Blanks
Q1
Quotient ← 17 DIV 5Q2
Remainder ← 17 MOD 5Q3
Average ← Total / CountQ4
Hours ← TotalMins DIV 60
Mins ← TotalMins MOD 60Q5
Mean ← (Score1 + Score2) / 2Section E: Spot the Error
Q1
C — DIV gives the whole-number quotient (3). The remainder is found with MOD, so the line should be Rem ← Num MOD 5, which gives 2.
Q2
B — MOD gives the remainder (15), not the number of whole hours. Whole hours need DIV: Hours ← Minutes DIV 60, which gives 2.
Q3
B — To test for an even number, check that the remainder after dividing by 2 is 0. That needs MOD, not DIV: IF Num MOD 2 = 0 THEN.
Q4
D — Division is done before addition, so only C is divided by 3. Brackets are needed to add first: Avg ← (A + B + C) / 3.
Q5
B — The letter x is not a multiplication operator in Cambridge pseudocode. Multiplication is *, so it should be Total ← Price * 3.